Question

1. Construct a triangle ABC in which BC = 7cm, tringleB= 75° and AB + AC = 13cm
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Answer 1

Answer:

(i) Draw BC = 7 cm.

(ii) Construct ∠YBC = 75°.

(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm.

(iv) Join CD.

(v) Draw the perpendicular bisector of CD meeting BY at A.

(vi) Join AC to obtain the required triangle ABC.

Step-by-step explanation:

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Answer 2

Answer:

STEPS OF CONSTRUCTION...

Steps of Construction

(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm. (iv) Join CD. (v) Draw the perpendicular bisector of CD meeting BY at A. (vi) Join AC to obtain the required triangle ABC.

JUSTIFICATION

Since A lies on the perpendicular bisector of CD.

Since A lies on the perpendicular bisector of CD.∴ AC = AD

Since A lies on the perpendicular bisector of CD.∴ AC = AD Now BD = 13 cm

Since A lies on the perpendicular bisector of CD.∴ AC = AD Now BD = 13 cm⇒ BA + AD = 13 cm

Since A lies on the perpendicular bisector of CD.∴ AC = AD Now BD = 13 cm⇒ BA + AD = 13 cm⇒ BA + BC = 13cm

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Hence, △ABC is the required triangle.