Question

1) Construct ALMN, such that, (LM)= 6.2cm. 7(LN) = 4.5 cm., I(MN) = 5 cm.
2) Yash has 10 rupee and 20 rupee notes. The number of 10 rupee notes is triple the number of 20 rupee notes. He had total 600 rupees. Then how many notes of 20 rupees he had?
3) Draw AABC such that, mZB = 40°, IAB) = ?(BC) = 6 cm. State which type of AABC is​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given Yash has 10 rupee and 20 rupee notes. The number of 10 rupee notes is triple the number of 20 rupee notes. He had total 600 rupees. Then how many notes of 20 rupees he had?

• So yash has 10 Rs and 20 Rs notes.
• According to the question the number of 10 Rs notes is triple the number of 20 Rs notes.
• So the total he had with him is Rs 600.
• We need to find the number of 20 Rs notes with him.
• Now let the number of 10 Rs note be m and 20 Rs note be n.
•           So we get m + n = 600
• According to the question m = 3 x n
•                                           m = 3n
• Substituting we get
•                          3n + n = 600
•                              4n = 600
•                                n = 600 / 4
•                              Or n = 150
• Therefore the number of 20 Rs notes that yash had is 150

Reference link will be

https://brainly.in/question/44443341