Question

1. Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90o.​

Answer 1

Answer:

To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90

o

.

Steps of construction:

(a) Draw a line segment DF=3cm

(b) At point D an angle of 90

o

with the help of compass i.e., ∠XDF=90

o

.

(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E

(d) Join EF

It is the required right angle triangle DEF

Answer 2

A triangle with DF= 3cm,DE= 5cm, ZEDF 90°