Question

1. Construct DEF such that DE-5cm, DF = 3 cm and EDF = 90°​

Answer 1

Answer:

Here it is.

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Step-by-step explanation:

To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90

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Steps of construction:

(a) Draw a line segment DF=3cm

(b) At point D an angle of 90

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with the help of compass i.e., ∠XDF=90

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(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E

(d) Join EF

It is the required right angle triangle DEF