Question

1) Construct ∆LMN such that angleM =70° , angleN =50° and LM+MN+LN =10CM.​

Answer 1

x added to -5.

z divided by 4.

9 added to x.

Decrease 11 by b.

1 more than z.

Answer 2

Step-by-step explanation:

Steps of construction:

(1) Draw seg AB of 11 cm length.

(2) Draw a ray making angle of 30° at point A.

(3) Draw another ray making an angle of 40° at point B.

(4) Name the point of intersection of the two rays as L.

(5) Draw the perpendicular bisector of seg AL and seg BL.

Name the points as M and N respectively where the perpendicular bisectors intersect line AB.

(6) Draw seg LM and seg LN.

Therefore, △LMN is the required triangle.