Question

1.construction a triangle PQR in which PQ=6.2cm,triangle p triangle Q=75°. now construct a line l from a point R parallel to PQ.​

Answer 1

Solution:

Given PQ=6.2 cm, ∠Q=60° & RQ−PR=3 cm

1) Draw PQ of length 6.2 cm using scale.

2) At point Q, draw ∠Q=60°

using protractor. Let the ray be QX.

3) Cut the line segment QY=3 cm (equal to RQ−PR=3 cm) on line QX.

5) Join PY and draw a perpendicular bisector AB of PY which cuts the line QX at point R.

6) Join P and R

Now, △PQR is the required triangle.

solution

Answer 2

Answer:

yes it is the right answer