Question

1) Convert a) 100 mA to A b)1.5 µA to A c) 6A to mA d) 3.5A to µA.
2) A solution of copper sulphate is electrolyzed for 10 in by passing 1.5 A
current. What is the next charge flowing across the solution?
3) Find the amount of current flowing if 150 C charge flows for 15 min in a) A
b) mA c) µA.

Answer 1

1. Solution :

(a) 100 mA = 100 × 10¯³ A = 0.1 A

(b) 1.5 μA = 1.5 × 10¯⁶ A

(c) 6A = 6000 × 10¯³ A = 6000 mA

(d) 3.5 A = 3.5 × 10⁶ × 10¯⁶ = 3500000 μA

2. We have to find the charge flowing across the solution.

solution : Q = it

Here , i = 1.5 A and t = 10 min

so, Q = 1.5 A × 10 × 60 sec

= 900 C

3. We have to find the amount of current if 150 C charge flows for 15 min.

Solution : current = charge/time

= 150C/(15 × 60) = 1/6 A

(a) 0.1667 A

(b) 166.7 mA

(c) 166700 μA