1. convex mirror with a radius of curvature of 3 m is used as rear view mirror for a vehic
If a bus is located at 5 m from this mirror, find the position, nature and size of the image
Answers
Answered by
47
Given
- Radius of curvature = 3 m
- Image position = 5 m
To Find
- The position, nature and size of the image
Solution
☯ 1/v + 1/u = 1/f
☯ M = -v/u
━━━━━━━━━━━━━━━━━━━━━━━━━
✭ According to the Question :
➞ 1/v + 1/u = 1/f
- v = ?
- u = -5
- f = 3/2
➞ 1/v + 1/(-5) = 2/3
➞ 1/v = 2/3 + 1/5
➞ 1/v = (10 + 3)/15
➞ 1/v = 13/15
➞ v = 15/13 m
➞ v = 1.15 m
━━━━━━━━━━━━━━━━━━━━━━━━━
Then the magnification of the image would be,
➞ M = -v/u
➞ M = -1.15/(-5)
➞ M = 0.23
Therefore,
- The image is virtual, erect, at 1.15 m & is diminished
Answered by
41
Answer:
Question :-
- Convex mirror with a radius of curvature of 3 m is used as rear view mirror for a vehic if a bus is located at 5 m from this mirror,
Find Out :
- The position, nature and size of the image.
Answer :-
Given :
➭ Radius = 3 m
➭ Image position = 5 m
We know that,
★ 1/v + 1/u = 1/f ★
➻ 1/v + 1/-5 = 2/3
➻ 1/v = 2/3 + 1/5
➻ 1/v = 10 + 3/5
➻ 1/v = 13/5
➻ v = 15/13
➠ v = 1.15 m
Hence, the image distance is 1.15 m.
Now, as we know that,
❖ m = - v/u ❖
➻ m = - (1.15)/- 5
➻ m = 1.15/5
➻ m = 115/5 × 100
➻ m = 23/100
➠ m = 0.03
∴ The image is erect, virtual and it is diminished.
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