Question

1+ cos 0+ sin /
1+ sin 0 cos 0 1+ cos 0-sin 0​

Answer 1

Answer:

$\frac{1+\cos \left(0\right)+\sin \left(x\right)}{1+\sin \left(0\right)\cos \left(1\right)+\cos \left(0\right)-\sin \left(0\right)}=\frac{\sin \left(x\right)+2}{2}$

Step-by-step explanation:

$\frac{1+\cos \left(0\right)+\sin \left(x\right)}{1+\sin \left(0\right)\cos \left(1\right)+\cos \left(0\right)-\sin \left(0\right)}$

$=\frac{\sin \left(x\right)+2}{1+\sin \left(0\right)\cos \left(1\right)+\cos \left(0\right)-\sin \left(0\right)}$

$=\frac{\sin \left(x\right)+2}{2}$