Math, asked by mspatel69500gm7, 11 months ago

√1-cos^2A · sec^2A= tanA​

Answers

Answered by ihrishi
0

Step-by-step explanation:

 \sqrt{(1 -  { \cos}^{2} A) \:  \: { \sec}^{2} A}  \\   \\ =  \sqrt{{ \sin}^{2} A \:  \: { \sec}^{2} A}  \\   \\ =  \sin \: A \:  \:   \sec \: A \:  \:  \\  \\  \sin \: A \times  \frac{1}{ \cos \: A}  \\  \\  = \frac{\sin \: A}{ \cos \: A}  \\  \\  =  \tan\: A \\  \\ thus \: proved

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