Question

1/cos^2Q - tan^2 0 = 1.
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Answer 1

LHS:

1/cos^2Q -tan^2Q

=sec^2Q-tan^2Q

1 proved

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Answer 2

$\huge\bf\red{answer}$

$\implies 1/cos^{2} \theta - tan^{2} \theta = 1\\ \implies 1/cos^{2}\theta- tan^{2}\theta \\ \implies sec^{2}\theta-tan^{2}\theta=1$

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