√(1-cos^2theta)sec^2theta=tantheta
Answers
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LHS
√[(1 - cos²θ)sec²θ]
= √[(sin²θ)sec²θ] [ using 1 - cos²θ = sin²θ ]
= √(sin²θ/cos²θ) [ using cosθ = 1/secθ ]
= √tan²θ [ since sinθ/cosθ = tanθ ]
= tanθ
RHS Hence Proved
Answered by
0
Answer:
tanθ
Step-by-step explanation:
√(1-cos^2θ)sec^2θ
√sin^2θ.sec^2θ
√sin^2θ. 1/cos^2θ
√tan^2θ
tanθ
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