1-cos^4A/sin^4A=1+2cot^2A prove
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Step-by-step explanation:
LHS
{1 - (cos^2A)^2} / (sin^2A)^2
a^2 - b^2 = (a+b)(a-b)
(1 - cos^2A)(1 + cos^2A) / (sin^2A)^2
we know that: sin^2A = 1 - cos^2A
= sin^2A(1 + cos^2) / sin^2A.sin^2A
= 1+cos^2A / sin^2A
= 1/sin^2A + cos^2A/sin^2A
= cosec^2A + cot^2A
formula - cosec^2A = 1 + cot^2A
= 1 + cot^2A + cot^2A
= 1 + 2cot^2A
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Answer:
i dont know
Step-by-step explanation:
i dont know
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