Question

√1+cos A ÷1- cos A + √ 1 - cos A÷. cos A = 2 cos A​

Answer 1

Step-by-step explanation:

$hope \: it \: will \: help \: u$

Answer 2

Answer:

$\frac{1 + cos \: a}{sin \: a} + \frac{sin \: a}{1 + cos \: a} = 2cosec \: a$

$\frac{(1 + cos \: a) {}^{2} + \: sin {}^{2} a }{sin \: a(1 + cos \: a)}$

$= > \: \frac{1 + cos {}^{2}a \: + 2cos \: a \: + sin {}^{2} a }{sin \: a \: (1 + cos \: a)}$

$= > \frac{2 + 2 \: cos \: a}{sin \: a \: (1 + cos \:a) }$

$= > \frac{2}{sin \: a}$

$= > 2 \times \frac{1}{sin \: a}$

$2cosec \: a \: = RHS$

$HENCE \: , \: PROVED$