1+cos a * 1-cos a = 3/4 find sec a
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Answered by
19
Step-by-step explanation:
given
1+cos a *1-cos a=3/4
1-cos²a=3/4
sin²a=3/4
sin a=√3/4
sin a=√3/2
by pathogorus theorem
h²=p²+b²
2²=√3²+b²
4=3+b²
b²=4-3
b²=1
b=√1=1
hence :-
the value of sec a=h/p=2/1=2
Answered by
2
Answer:
Step-by-step explanation:
1 - cos^2 a = 3/4
1 - 3/4 = cos^2a
4-3/4
1/4 = cos^2a
square root on both the sides
1/2 = cos a
sec a = 2
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