Math, asked by soumyadip231, 7 months ago

1+cos a/1 - cos a =(cosec a +cot a)^2 ​

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Answered by supreetkaur35
3

Answer:

taking \: left \: hand \: side \\  \\ by \: rationalising \\  \\  \frac{1 + cos \: a}{1 - cos \: a}  \times  \frac{1 + cos \: a}{1 + cos \: a}  \\  \\  =  \frac{ {(1 + cos \: a)}^{2} }{ {(1)}^{2} -  {(cos \: a)}^{2}  }   \\  \\  =  \frac{ {(1 + cos \: a)}^{2} }{1 -  {cos}^{2} a}  \\  \\  =  \frac{ {(1 + cos \: a)}^{2} }{ {sin }^{2} a}  \\  \\ =  ( \frac{1 + cos \: a}{sin \: a} )^{2}  \\  \\  = ( \frac{1}{sin \: a}  +  \frac{cos \: a}{sin \: a} )^{2}  \\  \\  = (cosec \: a + cot \: a)^{2}   \\  \\  = right \: hand \: side

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