1+cos A/1-cos A
please solve it
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It is ( cos e c A − cot A )^ 2
Explanation:
At first multiply and divide this with (1-cos A)
1 − cos A 1 + cos A ⋅ 1 − cos A 1− cos A = ( 1 − cos A) 2 1 − cos 2 A = ( 1 − cos A ) 2 sin 2 A = (1 sin A − cos A sin A ) 2 = ( cos e c A − cot A ) 2
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