Question

1 +cos A 1 −cos A = t a n A 2 s e c A − 1 2

Answer 1

Answer:

According to question,

secA+tanA

1

−

cosA

1

=

cosA

1

−

secA−tanA

1

⟹

secA+tanA

1

+

secA−tanA

1

=2secA

Solving LHS,

⟹

(secA+tanA)(secA−tanA)

secA−tanA+secA+tanA

⟹

sec

2

A−tan

2

A

2secA

⟹

1

2secA

⟹2secA = RHS

Hence proved

Hope it will help U:)