Question

(1 - cos A) (1 + sec A) = tan A sin A.​

Answer 1

sinA*sinA/cosA) /(1-cosA)

sin^2A/(cosA (1-cosA ))

(1-cos^2A)/ (cosA (1-cosA))

(1+cosA)(1-cosA) / (cosA (1-cosA))

(1+cosA)/cosA

(1/cosA)+(cosA/cosA)

secA+1

1+secA proved

please mark as BRAINliest answer

Answer 2

Step-by-step explanation:

(1-cosA)(1+secA)

(1-cosA)(1+1/cosA)

(1-cosA)(cosA+1/cosA)

(1-cosA)(1+cosA)/cosA

1-cos^2A/cosA

sin^2A/cosA

sinA×sinA/cosA

sinA.tanA