(1+cos A-cosecA) (1+tanA+secA) =2
Answers
Answered by
1
Step-by-step explanation:
= (1+cosa/sina-1/sina) (1+sina/cosa-1/cosa)
= (sina+cosa-1/sina) (cosa+sina-1/cosa)
= ((sina+cosa) - (1)/sina) ((cosa+sina) - (1)/cosa)
= ((sina+cosa)raise to power2 - (1)raise to power 2)/sinacosa
= sin2a+cos2a+2sinacosa-1/sinacosa
= 1+2sinacosa-1/sinacosa (because sin2a+cos2a=1)
= 2sinacosa/sinacosa
=2
=R.H.S
Similar questions
English,
3 months ago
English,
3 months ago
World Languages,
3 months ago
Hindi,
7 months ago
Science,
7 months ago
Science,
11 months ago
Social Sciences,
11 months ago