Question

(1+cos A-cosecA) (1+tanA+secA) =2​

Answer 1

Step-by-step explanation:

= (1+cosa/sina-1/sina) (1+sina/cosa-1/cosa)

= (sina+cosa-1/sina) (cosa+sina-1/cosa)

= ((sina+cosa) - (1)/sina) ((cosa+sina) - (1)/cosa)

= ((sina+cosa)raise to power2 - (1)raise to power 2)/sinacosa

= sin2a+cos2a+2sinacosa-1/sinacosa

= 1+2sinacosa-1/sinacosa   (because sin2a+cos2a=1)

= 2sinacosa/sinacosa

=2

=R.H.S