Question

1+cos a/sin a +sin a/1+cos a = 2 cosec a please help i'm blank

Answer 1

✳ Verified Answer

This is easy my dear. Here's a proof.

SinA/(1 + CosA) + (1 + CosA)/SinA

= [(SinA)^2 + (1+CosA)^2]/[SinA(1 + CosA)]

= [(SinA)^2 + (CosA)^2 + 1 + 2CosA]/[SinA(1 + CosA)]

= [2(1 + CosA)]/[SinA(1 + CosA)] ( since, (SinA)^2 + (CosA)^2 = 1 )

= 2/SinA = 2CosecA

Hence LHS=RHS.

That’s it, cake walk. Hope you understand.

Best wishes.

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Answer 2

Your answer is in the pic




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