Math, asked by yuvraj0065, 4 months ago

1 + cos A/sin A
sin A/1 +cos A
=2 cosecA.

Answers

Answered by rpnikhilverma
0

Answer:

we have

⇒LHS=  

1−sinA

cosA

​  

+  

1−cosA

sinA

​  

+1

⇒LHS=  

sinA(1−cosA)+(1−sinA)(1+cosA)

cosA(1−cosA)+sinA(1−cosA)+(1−sinA)(1+cosA)

​  

 

⇒LHS=  

sinA(1−cosA)+(1−sinA)(1+cosA)

cosA−cos  

2

A+sinA−sin  

2

A+1−sinA−cosA+sinAcosA

​  

 

⇒LHS=  

sinA(1−cosA)+(1−sinA)(1+cosA)

(cosA+sinA)−(cos  

2

A−sin  

2

A)+1−(cosA+,sinA)+sinAcosA

​  

 

⇒LHS=  

sinA(1−cosA)+(1−sinA)(1+cosA)

(cosA+sinA)−1+1−(cosA+sinA)+sinA+cosA

​  

 

⇒LHS=  

sinA(1−cosA)+(1−sinA)(1+cosA)

sinAcosA

​  

 =RHS

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