Question

1 + cos A /sin A = sin A / 1- cos A

Answer 1

take LHS

1+cos A/(sinA)

[2cos^2A/2]/2sinA/2 cos A/2

cot(A/2)

RHS

sinA/[1-cosA]

2sin(A/2)cos(A/2)/[2sin^2(A/2)]

cot(A/2)

lhs=RHS

Answer 2

Answer:

I HOPE THIS HELPS YOU......