Question

1 + Cos A upon 1 minus cos A is equals to 10 square upon sec a minus 1 whole square​

Answer 1

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Answer 2

Answer:

LHS : (1+cos(a))÷(1−cos(a))

RHS : (100/sec(a)×sec(a))

= (2.cos(a/2).cos(a/2))/

(2.sin(a/2).sin(a/2))

= cot(a/2)× cot(a/2) [LHS]

= 100×cos(a) ×cos(a) [RHS]

Thus RHS = 100×(2.cos(a/2)-1)^2

Now simplify