Question

1 + Cos A upon sin square is equal to 1 upon 1 minus Cos A​

Answer 1

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Answer 2

Question:-

(1 + CosA)/Sin²A = 1 / (1 - Cos A)

Solving Left Hand Side (LHS) :-

(1 + CosA) / Sin²A

=> (1 + CosA) / (1 - Cos²A)

[ By the identity :- Sin²A = 1 - Cos²A ]

=> (1 + CosA) / { (1)² - (CosA)² }

=> (1 + CosA) / (1 - CosA)(1 + CosA)

[ By the identity :- (a-b)(a+b) = a² - b² ]

=> 1 / (1 - CosA)

Now , LHS = RHS

Hence proved.