Question

1 - cos alpha into 1 - cos beta into 1 - cos gama is equal to one minus cos alpha into 1 + cos beta + into 1 - cos,

Answer 1

Answer:

Step-by-step explanation:

(1 + Cos alpha )( 1 + cos beta )( 1 + cos gamma) / ( 1 – cos alpha )( 1 – cos beta )( 1 – cos gamma ) =1

multiplying (1+ cos alpha)( 1+ cos beta )( 1+ cos gamma ) in both numerator and denominator ,

[(1 + cos alpha )( 1+ cos beta )( 1+ cos gamma )]2 / (1 – cos2alpha )( 1 – cos2beta )( 1 – cos 2gamma ) = 1

[(1 + cos alpha )( 1+ cos beta )( 1+ cos gamma )]2 / (sin2alpha)( sin2beta )( sin2gamma) = 1

[(1 + cos alpha )( 1+ cos beta )( 1+ cos gamma )]2 = (sin2alpha)( sin2beta )( sin2gamma)

(1 + cos alpha )( 1+ cos beta )( 1+ cos gamma ) = (sin alpha)( sin beta )( sin gamma)

Answer 2

Here is the solution

stepwise and simple