(1-cos square theta 1+cot square theta)
write the simplest form
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(1-cos square theta 1+cot square theta) = 1
Given,
(1-cos square theta 1+cot square theta)
= ( 1 - cos² ∅) ( 1 + cot² ∅ )
= 1 + cot² ∅ - cos² ∅ - cos² ∅ cot² ∅
= 1 + cos² ∅/sin² ∅ - cos² ∅ - cos² ∅ ( cos² ∅/sin² ∅ )
= ( 1 - cos² ∅ ) + cos² ∅/sin² ∅ - (cos² ∅ × cos² ∅) /sin² ∅
= sin² ∅ + cos² ∅ ( 1 - cos² ∅ ) /sin² ∅
= sin² ∅ + cos² ∅ ( sin² ∅ ) /sin² ∅
= sin² ∅ + cos² ∅ (1)
= sin² ∅ + cos² ∅
= 1
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