Question

1-cos theeta - sin sq.theeta / sintheeta ( 1+ cos theeta )= cot tyeeta

Answer 1

LHS = (1 + cosA - sin^2A) / sinA(1+cosA)
        = (cosA + cos^2A)  /  sinA(1 + cosA)
        = cosA(1+cosA)  /  sinA(1+cosA)
        = cosA / sinA
        = cot A

RHS = cotA

                   LHS = RHS

(note = theeta is A , here)    

Answer 2

hey !!!

From LHS

1 + cos¢ - sin²¢/ sin¢ (1 + cos¢ )

=> 1 - sin²¢ + cos¢ /sin¢ ( 1 + cos¢ )

=> cos²¢ + cis¢ / sin¢ (1 + cos ¢)

=> cos¢(1 + cos¢ )/ sin¢( 1 + cos ¢)

=> cos¢/sin¢

=> cot¢ RHS prooved.

hope it helps you ;!!!

#Rajukumar 111