Question

1-cos theta ÷ 1+cos theta = (cosec theta-cot theta)²​

Answer 1

$\frac{1 - cos \theta}{1 + cos \theta} \\ = \frac{1 - cos \theta}{1 + cos \theta} \times \frac{1 - co s\theta}{1 - cos \theta} \\ = \frac{( {1 - cos \theta})^{2} }{ {sin}^{2} \theta } \\ = ( { \frac{1 - cos \theta}{sin \theta} })^{2} \\ = ( {cosec \theta - cot \theta})^{2}$