Math, asked by bujjipragna179, 11 months ago

√1+cos theta/1-cos theta = (sec theta -tan theta)whole square

please answer

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Answered by lalitmohanlohani2018

1

Answer:

This is the correct ans ...........

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Answered by thakurrishabh0381rts

1

Answer:

LHS = √1+cos theta/1-cos theta

= √1+2cos^2¢ -1 / 1-1+2sin^2¢

= √cos^2¢/sin^2¢

= √cot^2¢

= cot¢

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