Question

1 + cos theta by sin theta whole square equal to 1 + cos theta by 1 - cos theta prove that​

Answer 1

i hope this will hope you.

Answer 2

Answer:

$\dfrac{(1+cos\theta)^2}{(sin\theta)^2}\\\\\implies \dfrac{(1+cos\theta)^2}{sin^2\theta}\\\\\implies \dfrac{(1+cos\theta)^2}{1-cos^2\theta}\\\\\implies \dfrac{(1+cos\theta)^2}{(1+cos\theta)(1-cos\theta)}\\\\\implies \dfrac{1+cos\theta}{1-cos\theta}$

L.H.S = R.H.S [ Hence Proved ]

Step-by-step explanation:

Formulas used :

sin²Ф = 1 - cos²Ф

a² - b² = (a + b)(a - b)