Question

1/cos theta-cos theta=(tan theta)sin theta​

Answer 1

Answer:

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Answer 2

$= \frac{1}{ \cos( \alpha ) } - \cos( \alpha ) \\ = \frac{1 - \cos {}^{2} ( \alpha ) }{ \cos( \alpha ) } \\ = \frac{ \sin {}^{2} ( \alpha ) }{ \cos( \alpha ) } \\ = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \times \sin( \alpha ) \\ = \tan( \alpha ) \times \sin( \alpha )$

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