Question

1+cos theta divided by sintheta - sin theta divided by 1+cos theta =2 cot theta​

Answer 1

Answer:

Hey mate here is your answer...

$\frac{1 + \cos( \beta ) }{ \sin( \beta ) } - \frac{ \sin( \beta ) }{1 + \cos( \beta ) } = 2 \cot( \beta ) \\ \frac{(1 + \cos( \beta )) {}^{2} - \sin ^{2} ( \beta ) }{ \sin( \beta) (1 + \cos( \beta ) ) } \\ \frac{1 + \cos( \beta ) ^{2} + 2 \cos( \beta ) - \sin {}^{2} ( \beta ) }{ \sin( \beta )(1 + \cos( \beta ) )} \\ \frac{ \cos {}^{2} ( \beta ) + \cos {}^{2} ( \beta ) + 2 \cos( \beta ) }{ \sin( \beta )(1 + \cos( \beta ) ) } \\ \frac{2 \cos {}^{2} ( \beta ) + 2 \cos( \beta ) }{ \sin( \beta )(1 + \cos( \beta ) )} \\ \frac{2 \cos( \beta )( \cos( \beta ) + 1) }{ \sin( \beta ) (1 + \cos( \beta ) )} \\ \frac{2 \cos( \beta ) }{ \sin( \beta ) } \\ 2 \cot( \beta )$

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Answer 2

Answer:    [HENCE PROVED]

Step-by-step explanation: