1 + cos theta - sin^2 theta divided by sin ( 1 + cos theta) = cot theta
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Hence proved
Hope it will work
Hope it will work
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1-sin²@=cos²@
so,1+cos@-sin²@/sin(1+cos@)=cos²@+cos@/sin(1+cos@)=cos@(1+cos@)/sin@(1+cos@)=cos@/sin@=cot@
so,1+cos@-sin²@/sin(1+cos@)=cos²@+cos@/sin(1+cos@)=cos@(1+cos@)/sin@(1+cos@)=cos@/sin@=cot@
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