1+cos theta -sin^2 theta / sin theta (1 + cos theta ) = cot theta
Answers
Answered by
84
1+cosθ-sin²θ/sinθ(1+cosθ)=cotθ
or 1+cosθ-sin²θ+cos²θ-cos²θ/sinθ(1+cosθ)=cotθ
or cosθ+cos²θ/sinθ(1+cosθ)=cotθ
or cosθ(1+cosθ)/sinθ(1+cosθ)=cotθ
or cosθ/sinθ=cotθ
or cotθ=cotθ
We know,cos/sin=cot
So,LHS=RHS,hence,verified
or 1+cosθ-sin²θ+cos²θ-cos²θ/sinθ(1+cosθ)=cotθ
or cosθ+cos²θ/sinθ(1+cosθ)=cotθ
or cosθ(1+cosθ)/sinθ(1+cosθ)=cotθ
or cosθ/sinθ=cotθ
or cotθ=cotθ
We know,cos/sin=cot
So,LHS=RHS,hence,verified
Answered by
160
Your answer is in the attachment and pls mark the brainleist
Attachments:
Similar questions
English,
7 months ago
Math,
7 months ago
Chemistry,
1 year ago
Computer Science,
1 year ago
Biology,
1 year ago