Question

1+cos theta-sin sq. Theta/sin theta (1+cos theta)=cot theta

Answer 1

Hi ,

Here I am using A instead of theta.

LHS = (1+cosA - sin²A )/sinA(1 + cosA )

= ( 1 - sin²A + cosA )/sinA( 1 + cosA )

= ( cos²A + cosA )/sinA( 1 + cosA )

= [ cosA ( cosA + 1 )]/sinA( cosA + 1 )

after cancellation ,

= cosA/sinA

= cotA

= RHS

I hope this helps you.

: )

Answer 2

hey mate here is ur answer:-