1 - cos theta / sin theta = ?
answers fast please
Answers
Answer:
First use the identities,
\begin{gathered}1-\cos \theta = 2\sin^2(\frac{\theta}{2}) \\ \sin \theta =2\sin(\frac{\theta}{2}) \cos(\frac{\theta}{2})\end{gathered}
1−cosθ=2sin
2
(
2
θ
)
sinθ=2sin(
2
θ
)cos(
2
θ
)
So,
\begin{gathered}LHS=\frac{1-\cos \theta }{\sin \theta}\\ LHS=\frac{2\sin^2(\frac{\theta}{2}) }{2\sin(\frac{\theta}{2}) \cos(\frac{\theta}{2}) }\\ LHS=\frac{\sin(\frac{\theta}{2}) }{ \cos(\frac{\theta}{2}) }\\ LHS=\tan(\frac{\theta}{2}) =RHS\end{gathered}
LHS=
sinθ
1−cosθ
LHS=
2sin(
2
θ
)cos(
2
θ
)
2sin
2
(
2
θ
)
LHS=
cos(
2
θ
)
sin(
2
θ
)
LHS=tan(
2
θ
)=RHS
The proof is complete.
Step-by-step explanation:
Follow me
Step-by-step explanation:
1-cos theta
i hope it helps you
and y u had kept this thanks I am in village
for that I didn't saw sorry
have u went to school
and this is not my phone my Mama's phone for that I can't chat more ok na
and what that answer that u answered I didn't saw IAM eating noodles