Math, asked by Fiora123, 2 months ago

1/cos theta+ sin theta/cos theta = 2+√3
Q. What is value of theta?

Answers

Answered by s1263nishani7886
1

Step-by-step explanation:

identities

\sec(\theta)= \dfrac{1}{\cos(\theta)}sec(θ)=

cos(θ)

1

\sec, left parenthesis, theta, right parenthesis, equals, start fraction, 1, divided by, cosine, left parenthesis, theta, right parenthesis, end fraction

Explain

\csc(\theta)= \dfrac{1}{\sin(\theta)}csc(θ)=

sin(θ)

1

\csc, left parenthesis, theta, right parenthesis, equals, start fraction, 1, divided by, sine, left parenthesis, theta, right parenthesis, end fraction

Explain

\cot(\theta)= \dfrac{1}{\tan(\theta)}cot(θ)=

tan(θ)

1

cotangent, left parenthesis, theta, right parenthesis, equals, start fraction, 1, divided by, tangent, left parenthesis, theta, right parenthesis, end fraction

Explain

\tan(\theta)= \dfrac{\sin(\theta)}{\cos(\theta)}tan(θ)=

cos(θ)

sin(θ)

tangent, left parenthesis, theta, right parenthesis, equals, start fraction, sine, left parenthesis, theta, right parenthesis, divided by, cosine, left parenthesis, theta, right parenthesis, end fraction

Explain

\cot(\theta)= \dfrac{\cos(\theta)}{\sin(\theta)}cot(θ)=

sin(θ)

cos(θ)

Answered by sijit1981
1

Answer:

1×cosθ+

3

sinθ=2

⇒(

2

1

cosθ+

2

3

sinθ)=1

⇒sin30

0

cosθ+cos30

0

sinθ=1

⇒sin(θ+30

0

)=sin90

0

⇒θ+30

0

=90

0

orθ=60

0

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