1 - cos theta + sin theta into 1 + cos theta + sin theta equals to 2 Sin Theta into 1 + sin theta
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(1-cos theta+sin theta)(1+cos theta + sin theta)
= (1+sin theta - cos theta)(1+sin theta + cos theta)........(1)
let a = 1+sin theta and b= cos theta
by using formula
(a-b)(a+b)= a^2 - b^2. in first equation
(1+sin theta)^2 - cos^2 theta
= 1+sin^2 theta + 2sin theta - cos^2theta
= 1-cos^2 theta + sin^2 theta +2sin theta
= sin^2 theta + sin^2 theta + 2sin theta
= 2 sin^2 theta + 2sin theta
= 2 sin theta (sin theta + 1)
hence proved
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