1-cos theta /sin theta =sin theta / 1+cos theta
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Answered by
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1-cos theta/sin theta = sin theta /1+ cost theta
cross multiplying
(1-cos theta )(1+cos theta)=(sin theta )(sin theta)
Here (a+b)(a-b)=a^2-b^2 is used
so,1^2-costheta^2=sin theta^2
1-costheta^2=sintheta^2
By identity 1
sin ^2=1-cos^2
Answered by
17
Answer:
1-cos theta/sin theta = sin theta /1+ cost theta
cross multiplying
(1-cos theta )(1+cos theta)=(sin theta )(sin theta)
Here (a+b)(a-b)=a^2-b^2 is used
so,1^2-costheta^2=sin theta^2
1-costheta^2=sintheta^2
By identity 1
sin ^2=1-cos^2
Step-by-step explanation:
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