1-cos theta /sin theta = sin theta/ 1+cos theta prove it
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=> (1 - cos(theta))/sin(theta)
=>(1 - cos(theta)(1 + cos(theta))/sin(theta)(1 + cos(theta))
=>(1 + cos^²(theta))/sin(theta)
=>sin^²(theta)/(1 + cos(theta). [sin^²(theta) = (1 \: - \: cos^²(theta))]
=>sin(theta)/(1 + cos(theta)
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