Math, asked by sowmiya35, 1 year ago

1 + cos theta + sin theta upon 1 + cos theta minus sin theta equal to 1 + sin theta upon cos theta

Answers

Answered by Anonymous

( 1 + cos x + sin x ) / ( 1 + cos x - sin x )

= cos x ( 1 + cos x + sin x ) / cos x ( 1 + cos x - sin x )

= ( cos x + cos²x + cos x sin x ) / cos x ( 1 + cos x - sin x )

= ( cos x ( 1 + sin x ) + 1 - sin² x ) ) / cos x ( 1 + cos x - sin x )

= ( cos x ( 1 + sin x ) + ( 1 + sin x )( 1 - sin x ) / cos x ( 1 + cos x - sin x )

= ( 1 + sin x )( 1 + cos x - sin x ) / cos x ( 1 + cos x - sin x )

= ( 1 + sin x ) / cos x

sowmiya35: what you did in the 2nd step

sowmiya35: please answer me

Anonymous: a / b can be written as cos a / cos b . multiply the denominator and numerator both by cos x .

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