1 + cos thetha / 1 - cos thetha = ( cosec thethe + cot thetha )²
Answers
Answered by
2
Answer:
We have,
(cosecθ−cotθ)
2
=(
sinθ
1
−
sinθ
cos θ
)
2
=(
sinθ
1−cosθ
)
2
=
sin
2
θ
(1−cosθ)
2
=
1−cos
2
θ
(1−cosθ)
2
[∵sin
2
θ=1−cos
2
θ]
=
(1−cosθ)(1+cosθ)
(1−cosθ)
2
=
1+cosθ
1−cosθ
.
Step-by-step explanation:
Answered by
0
Answer:
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