1+cos thita/sin thita
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(1+cosA)²+(sin²A)/sinA.(1+cosA)
(1+cos²A+ 2cosA +sin²A)÷ ( sinA(1+cosA))
(1+cos²A+sin²A+2cosA) ÷ (sinA(1+cosA))
(1+1+2cisA)/(sinA(1+cisA))
2+2cosA ÷ (sinA(1+cosA))
2(1+cosA) / sinA( ( 1+cosA))
2/sinA
2cosecA
if it helps you please make the brainliest answer
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