Question

1+cos titha+sin titha/1+cos titha-sin titha=1+sin titha cos titha​

Answer 1

Answer:

Hope it's correct thank you ~♥~

Answer 2

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Step-by-step explanation:

cos2θ(1tanθ)+sin3θ(sinθ-cosθ)=(1+sinθcosθ)

LHS= cos2θ(1-tanθ)+sin3θ(sinθ-cosθ)

= cos2θ1-sinθcosθ+sin3θ(sinθ-cosθ)

= cos3θ(cosθ-sinθ)+sin3θ(sinθ-cosθ)

= cos3θ-sin3θ(cosθ-sinθ)

=

(cosθ-sinθ)(cos2θ+cosθsin+sin2θ)(cosθ-sinθ)

= (sin2θ+cos2θ+cosθsinθ)

= (1+sinθcosθ)

=RHS

Hence, L.H.S = R.H.S.