Question

1) cos(π–x) = ?
2) cos (π/2+x) =?
3) sin(π–x) = ?
4) sin(π/2+x) =?

Answer 1

1) cos(π–x) = cosx
2) cos (π/2+x) =-sinx
3) sin(π–x) = sinx
4) sin(π/2+x) =cosx

Answer 2

1). cos(π-x) = -cosx.
( as cos is negative in IInd quadrant and because of π trigonometric ratio will not change. )

2). cos(π/2 + x) = -sinx
( as cos is negative in IInd quadrant and because of π/2 trigonometric ratio will change. )

3).sin(π-x) = sinx
( as sin is positive in IInd quadrant and because of π trigonometric ratio will not change. )

4). sin(π/2 + x) = cosx
( as. sin is positive in IInd quadrant and because of π trigonometric ratio will change. )

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