1- cos x cos 2x cos 3x
lim
sin 2x
cosx cos
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Answer:
Step-by-step explanation:
We have cos x cos2x cos 3x
= 1/2(2 cos 3x cos x) cos2x
= 1/2(cos 4x + cos 2x) cos2x
= 1/4(2 cos 4x cos2x + 2cos22x)
= 1/4(cos 6x + cos2x + 1 + cos 4x)
= 1/4(1 + cos 2x + cos4x + cos6x)
Thus
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