(1+cos²Φ)(1-cosΦ)(1+cosΦ)=1
Sharon15:
is your statement correct......plz check??
sorry
it have must been (1+cot²Φ)
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Hi dear RISHA in your question it is (1+cot²Φ) instead of (1+cos²Φ) OK.
NOW answer =>(1+cot²Φ)(1-cosΦ)(1+cosΦ) = 1
L. H. S. (1+cot²Φ)1(1+cosΦ)-cosΦ(1+cosΦ)
(1+cot²Φ)(1+cosΦ-cosΦ-cos²Φ)
(1+cot²Φ)(1-cos²Φ) [1+cot²Φ=cosec²Φ, 1-cos²Φ=sin²Φ]
cosec²Φ.sin²Φ
cosec²Φ1/cosec²Φ
1=1. (proved)
it will help completely.
u will understand.
/THANKS /
NOW answer =>(1+cot²Φ)(1-cosΦ)(1+cosΦ) = 1
L. H. S. (1+cot²Φ)1(1+cosΦ)-cosΦ(1+cosΦ)
(1+cot²Φ)(1+cosΦ-cosΦ-cos²Φ)
(1+cot²Φ)(1-cos²Φ) [1+cot²Φ=cosec²Φ, 1-cos²Φ=sin²Φ]
cosec²Φ.sin²Φ
cosec²Φ1/cosec²Φ
1=1. (proved)
it will help completely.
u will understand.
/THANKS /
sorey i didnot get ur point...the question i haved typed is absolutely correct
oops sorry
its was my fault
ok dear it's all right be happy
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