Question

1-cos2θ+sin2θ/1+sin2θ+cos2θ = tanθ

help me prove this

"note 2 in cos2θ and other arent square"

Answer 1

ANSWER

L.H.S= (

1+cos2θ+sin2θ

1−cos2θ+sin2θ

)

=(

1+(2cos

2

θ−1)+2sinθcosθ

1−(1−2sin

2

θ)+2sinθcosθ

)

=(

2cosθ(cosθ+sinθ)

2sinθ(sinθ+cosθ)

)

=tanθ=RHS

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