Math, asked by kushaldave2002, 1 year ago

1÷cos290+1÷root3*sin250

Answers

Answered by siya2908gemailcom

1/cos290+1/root3.sin250

=1/sin20 -1/root3.cos20

=root3cos20-sin20/root3.sin20.cos20

=4.(sin60co20-cos60sin20)/root3.2sin20cos20 [multiply and divide by 4]

=4sin40/root3.sin40= 4/root3

Thanks & Regards

Sunil Raikwar

askIITians Faculty

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